0=-16x^2+45x+112

Solution for 0=-16x^2+45x+112 equation:

0=-16x^2+45x+112

We move all terms to the left:

0-(-16x^2+45x+112)=0

We add all the numbers together, and all the variables

-(-16x^2+45x+112)=0

We get rid of parentheses

16x^2-45x-112=0

a = 16; b = -45; c = -112;
Δ = b2-4ac
Δ = -452-4·16·(-112)
Δ = 9193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{9193}}{2*16}=\frac{45-\sqrt{9193}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{9193}}{2*16}=\frac{45+\sqrt{9193}}{32}
$